-12x+36=-x^2

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Solution for -12x+36=-x^2 equation: 



-12x+36=-x^2

We move all terms to the left:

-12x+36-(-x^2)=0

We get rid of parentheses

x^2-12x+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{2}=6$

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